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0=2x^2-5x-11
We move all terms to the left:
0-(2x^2-5x-11)=0
We add all the numbers together, and all the variables
-(2x^2-5x-11)=0
We get rid of parentheses
-2x^2+5x+11=0
a = -2; b = 5; c = +11;
Δ = b2-4ac
Δ = 52-4·(-2)·11
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{113}}{2*-2}=\frac{-5-\sqrt{113}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{113}}{2*-2}=\frac{-5+\sqrt{113}}{-4} $
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